Sunday, April 11, 2021

Improving Reasoning: Analysing Alternative ApproachesbAge 5 to 18

<script async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js?client=ca-pub-6052001122903465"
     crossorigin="anonymous"></script>
<!-- Coffee -->
<ins class="adsbygoogle"
     style="display:block"
     data-ad-client="ca-pub-6052001122903465"
     data-ad-slot="8921372125"
     data-ad-format="auto"
     data-full-width-responsive="true"></ins>
<script>
     (adsbygoogle = window.adsbygoogle || []).push({});
</script>
Everyone agrees that it is important to develop reasoning in mathematics lessons. It is a main objective of mathematics curricula around the world[1], but the evidence from most classrooms seems to show that reasoning is insufficiently developed[2]. Why should this be?

After many years watching and designing mathematics lessons, it has become clear to me that most of the attention is on 'answer-getting', not on improving the quality of the reasoning. As soon as pupils get the answer, they are moved onto a fresh problem, they don't reflect much on the process they went through. Reasoning is not improved because it does not become the object of attention. Most reasoning remains invisible ' it stays inside people's heads. In order for students to improve their reasoning, it needs to be made visible and audible ' through oral or written explanations.

Recently, at Nottingham, we have been trying out a model for the design of 'formative' mathematics lessons that try to address this issue. This approach encourages pupils to stick with a problem and revise and refine their solutions over two lessons. The plan is as follows:

First lesson:

Introduce a challenging problem to the class and allow pupils to have a go at it, individually, without help. The intention here is to allow pupils time to engage with the problem and to explore some possible approaches. Most pupils may not get very far and will need reassuring that this doesn't matter.

Collect in pupils' initial ideas and look through them. Don't mark the work, but try to get an overview of pupils' ideas and existing ways of thinking. Prepare a few oral questions that you can give to move their thinking forward. These questions should not be about 'getting pupils to an answer', but rather about deepening their thinking. So 'can you think of a more helpful representation?' is better than 'why don't you try drawing a graph?'

Second lesson:

Re-issue the problem and allow pupils time to work in pairs, sharing their different approaches. Where necessary, prompt pupils with the prepared questions.

Allow pupils time to have a second go at the problem producing a joint attempt. If this part is produced on a poster, a few pairs can be asked to share their thinking with the whole class. Encourage questions and suggestions from other pupils as they do this.

Give each pair of pupils some written examples of other pupils' reasoning ('sample work'). These should show a range of possible approaches. For example, they may show a numerical, a graphical and an algebraic approach. These examples shouldn't be complete or perfect, because you want pupils to critique and improve them.

Finally, ask pupils to work together to produce an elegant, complete, polished solution.
 

We have tried this approach now in many classrooms with a wide range of problems. What we have found is that the quality of the solutions improves quite dramatically. What is even more remarkable though, is how much pupils' reasoning develops.

The role of the sample work seems to be a key factor in this. In concept-focused lessons, the sample work may be chosen to illustrate common mistakes and misconceptions. In problem-solving lessons the sample work may focus on alternative approaches. In each case the sample work makes the reasoning visible.

An important feature of problem solving is that pupils are given an opportunity to select and apply any method they choose from their mathematical 'toolkit'. But this leads to a dilemma:

Given the choice, pupils only use mathematics with which they are comfortable, like trial and error. They don't choose algebra! They never realise the potential of more sophisticated methods.

If they are told which methods to use, then problems degenerate into technical exercises and pupils never learn to use mathematics autonomously.

This dilemma can be resolved using the sample work. After having a go at the problem themselves, pupils are confronted with a series of potential approaches that show ways of thinking that contrast with their own. They are encouraged to engage with each piece of reasoning, first to comprehend it, then to improve and complete it. Pupils develop critical skills during this process. Compared with teacher-provided methods, sample pupil reasoning has less status, and pupils enjoy challenging it.

When we tried out this approach with teachers, some used authentic samples of work taken from their own classroom, while others created 'fake' sample work designed to illustrate particular learning points. Some commented that social issues interfered when the reasoning came from other pupils in the same class - pupils became less critical when commenting on work produced by friends. In our work we prefer to base the work on authentic examples, but rewrite them to make them anonymous.

In this month's NRICH problems there are many opportunities for pupils to analyse reasoning in the sample approaches. In Lots of Lollies, for example, after pupils have had time to try the problem themselves, they are given two partial solutions, one numerical and one diagrammatic, and are asked to think how these could be extended to form a solution. In Fitted, a practical approach is also included. In Steel Cables, four different correct approaches are shown that lead to the same solution. Here the challenge is to make sense of each solution and decide on a 'favourite'. (Actually my favourite isn't there - it involves seeing the figure as the difference of two cubes!). This could lead to discussion of such issues as 'elegance'. In Odds, Evens and More Evens, three starting points are given, each of which involves seeing the sequences of numbers in different ways.

 

I hope you will try to engage pupils with reasoning not just with these problems, but with many problems of your own.   

  

Finally, how often do we let pupils see us reasoning? One final challenge then! Choose a problem from the NRICH website that you have never seen before. Try to tackle it with a class, thinking aloud. Try different approaches. Ask the class to help with ideas when you get stuck. Go down blind alleys. If you get nowhere, then park the problem overnight and return to it later. If students are to learn what thinking like a mathematician is like, let them hear your thinking!

Quiz

Monday, March 22, 2021

Vedic Maths Tricks: Calculate 10x Faster


1. Squaring Of A Number Whose Unit Digit Is 5

With this Vedic Math trick, you can quickly find the square of a two-digit number ending with 5.
CBSE or ICSE-whatever syllabus you follow, you will definitely come across such sums.

For example Find (55) ² =?

Step 1. 55 x 55 = . . 25 (end terms)
Step 2. 5x (5+1) = 30

So our answer will be 3025.

Well, if you have understood the process try to find the square of 75 & 95.



2. Multiply a Number By 5

Generally, you come across such calculations in ICSE/ CBSE exams or homework or while thinking mentally (JEE, KVPY, Olympiad & lot more) to solve a Math problem. Next time use this trick to save your time.

Take any number, and depending on its even or odd nature, divide the number by 2 (get half of the number).

Even Number:

2464 x 5 =?
Step 1. 2464 / 2 = 1232
Step 2. add 0
The answer will be 2464 x 5 = 12320

Odd Number:

3775 x 5
Step 1. Odd number; so ( 3775 - 1) / 2 = 1887
Step 2. As it is an odd number, so instead of 0 we will put 5
The answer will be 3775 x 5 = 18875

Time to check your knowledge:

Now try —- 1234 x 5, 123 x 5

Friday, March 19, 2021

Vedic Maths Tricks: Calculate 10x Faster

Q. Dividing A Large Number By 5

Tell me, how do you generally divide a large digit number by 5? And, how much time do you take to solve such sums? Here is your challenge-

divide 2128 by 5. Before you start, start the timer.

Done in 2 secs? Ok! 4 secs? No? Well, next time divide the number using this Vedic Trick and note down the time taken to solve the sum.

So, what are the steps?

1st step. Multiply the number by 2
2nd step: Move the decimal point to left.
3rd step: Left side of the decimal point is your answer.

For example: 245 / 5 =?
Step 1. 245 * 2 = 490
Step 2. Move the decimal: 49.0 or just 49

Let’s try another: 2129 / 5
Step 1: 2129 * 2 = 4258
Step2: Move the decimal: 425.8 or just 425

Now you try to solve 16951/5, 2112/5, 4731/5

Q. Multiply Any Two-digit Number By 11

Use this Vedic Math trick to complete multiplication sin just 2 seconds. So, let’s see how you can reduce your calculation using this Vedic Trick.

For example:

32 x 11

32 * 11 = 3 (3+2) 2 = 352
So, the answer is: 32 * 11 =352

Another Example:

52 x 11 = 5 (5+2) 2 = 572

Now try 35*11, 19*11, 18*11.

Wednesday, March 17, 2021

Vedic Maths Tricks: Calculate 10x Faster

1. Subtraction From 1000, 10000, 100000

Tell me, how much time will you take to subtract a number from 100’s multiple such as 1000, 1000, 10000? 1 min or less? Leave that, try to calculate with this new formula and think if it’s easy & reduce your calculation time or not!

For example:
1000 – 573 =? (Subtraction from 1000)

We simply subtract each figure in 573 from 9 and then subtract the last figure from 10.
Step 1. 9 – 5 = 4
Step 2. 9 – 7 = 2
Step 3. 10 – 3 = 7

So, the answer is: (1000 – 573) = 427

Here are some practice sums for you. Try to solve these sums using the mentioned Vedic Math Tricks.

1000 – 857, 10,000 – 1029, 10,000 – 1264, 1000 – 336.

2. Multiplication Of Any 2-digit Numbers (11 - 19)

Till Math is there, you need to do such calculation each & every day, whether you are from CBSE board or ICSE Board. This Vedic Trick is especially for getting the result when you multiply any two-digit number from 11 to 19.

Once you practice this Vedic Trick for a number of times, you might never need a calculator to get the result as you will calculate faster than the machine.

There are 4 steps to get the result:

Step 1. Add the unit digit of the smaller number to the larger number.
Step 2. Next, multiply the result by 10.
Step 3. Now, multiply the unit digits of both the 2-digit numbers.
Step 4. Then add both the numbers.

For example: Let’s take two numbers 13 & 15.
Step 1. 15 + 3 =18.
Step 2. 18*10 = 180.
Step 3. 3*5 = 15
Step 4. Add the two numbers, 180+15 and the answer is 195.

Hope you have understood this Vedic Math Trick. It might seem a bit complex at first, but trust me once you master it, your calculation speed will increase by at least 80%. And, that is something every student needs to score well in Math!

Using this Vedic Trick, solve these sums and share your result: 15*18, 11*13, 19*19

Monday, March 15, 2021

Vedic Maths Tricks: Calculate 10x Faster

Q. Multiplication Of Any 3-digit Numbers

Suppose you want to multiply these 2 numbers: 306 and 308

Step 1. Now subtract the unit place digit from the actual number.
308-8=300
306-6=300

Step 2. Now select any (1st or 2nd) number and add the unit digit of the other number
308+6=314

Step 3. Now we will multiply the product we got in step 2 and step 1; 314×300 = 94200

Step 4. Unit digits of both the numbers are 8 & 6. The product of these 2 numbers: 8×6=48

Step 5. Last step: 94200 + 48 = 94248

So our final answer 306 x 308 = 306 is 94248

Solve these sums using the same method and feel the difference- 808*206, 536*504, 408*416.

Q. Find The Square Value

Finding the square of a number in using Vedic Maths Trick is easy. Just follow the below steps:

Step 1.Choose a base closer to the original number.
Step 2. Find the difference of the number from the base.
Step 3. Add the difference with the original number.
Step 4. Multiply the result with the base.
Step 5. Add the product of the square of the difference with the result of the above point.

(99) ² =?

Step 1. Choose 100 as base
Step 2. Difference: 99-100 = -1
Step 3. Add the number with the difference that you got in Step 2 = 99 + (-1) = 98
Step 4. Multiplying result with base = 98*100 = 9800
Step 5. Now, add result with the square of the difference= 9800 + (-1)² = 9801
So our answer is : (99) ² = 9801

For your practice: (98)², (97)², (102)², (101)².

If you check any competitive exam paper, you will find a lot of Math problems that can be solved easily & quickly using these Vedic Math Tricks. Not only for competitive exams like Olympiad, KVPY, JEE but also you can use these Vedic Math tricks in your regular school studies to increase speed & accuracy